Administrators Teddy Posted July 19 Administrators Share Posted July 19 A user recently asked "How do I implement a hyperbolic tangent function in Seeq?" Link to comment Share on other sites More sharing options...
Administrators Solution Teddy Posted July 19 Author Administrators Solution Share Posted July 19 Unfortunately, Seeq does not support the hyperbolic tangent function directly. However, it does support the exponential function so re-creating the hyperbolic tangent function is fairly simple. The formula below can be used to achieve the same result as a tanh or hyperbolic tangent. (Constant.E ^ (2*$x )- 1)/(Constant.E ^(2*$x) + 1) Note: To create and exponent in Seeq (e^x) you need to use Constant.E^x. Link to comment Share on other sites More sharing options...
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